0.01650g of an organic compound on a combustion analysis give 0.03153g CO2 and 0.01937g H2O. What is the percentage of C and H in compound? Also calculate the empirical formula.
Solution:-
wt of sample = 0.01650g
wt of CO2 = 0.03153g M.wt of CO2 = 44g/mol
wt of H2O = 0.01937g = M.wt of H2O = 18g/mol
Now
1 mole (44g) CO2 contain C = 12g
0.0315g CO2 contain C = = 0.0085909 g
It means that
0.01650 g sample contain C = 0.0085909g
100g sample contain C = x 100
= 52.07% C
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